The period of a mass-spring oscillator increases with:

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $25.99Unlock all

Prepare for the OnRamps Physics Test with our comprehensive quiz. Engage with flashcards, multiple choice questions, detailed hints, and explanations. Elevate your understanding and boost your confidence for the exam!

Multiple Choice

The period of a mass-spring oscillator increases with:

Explanation:
The period of a mass-spring oscillator depends on mass and spring stiffness, given by T = 2π sqrt(m/k). The square root means that increasing the mass makes the period longer, since more inertia takes longer to complete each cycle, while increasing the spring constant makes the motion stiffer and the cycle faster, shortening the period. So the period increases with mass and decreases with the spring constant. This matches the described relationship.

The period of a mass-spring oscillator depends on mass and spring stiffness, given by T = 2π sqrt(m/k). The square root means that increasing the mass makes the period longer, since more inertia takes longer to complete each cycle, while increasing the spring constant makes the motion stiffer and the cycle faster, shortening the period. So the period increases with mass and decreases with the spring constant. This matches the described relationship.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy