In an open-open tube of length L = 0.34 m and sound speed 340 m/s, what is the frequency of the second harmonic?

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Multiple Choice

In an open-open tube of length L = 0.34 m and sound speed 340 m/s, what is the frequency of the second harmonic?

Explanation:
Open-open tubes support standing waves with both ends free, so the allowed wavelengths satisfy L = nλ/2. The frequency follows f_n = v/λ = v n / 2L. With radius v = 340 m/s and length L = 0.34 m, the second harmonic uses n = 2, giving f_2 = (2)(340) / (2 × 0.34) = 340 / 0.34 = 1000 Hz. So the second harmonic has frequency 1000 Hz (twice the fundamental, which is 500 Hz since f1 = v/(2L) = 340/0.68 = 500 Hz).

Open-open tubes support standing waves with both ends free, so the allowed wavelengths satisfy L = nλ/2. The frequency follows f_n = v/λ = v n / 2L. With radius v = 340 m/s and length L = 0.34 m, the second harmonic uses n = 2, giving f_2 = (2)(340) / (2 × 0.34) = 340 / 0.34 = 1000 Hz. So the second harmonic has frequency 1000 Hz (twice the fundamental, which is 500 Hz since f1 = v/(2L) = 340/0.68 = 500 Hz).

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