In a tube closed at one end, the fundamental frequency f1 is related to v and L by f1 = v/(4L). If v = 340 m/s and L = 0.85 m, what is f1 when L doubles to 1.70 m?

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Multiple Choice

In a tube closed at one end, the fundamental frequency f1 is related to v and L by f1 = v/(4L). If v = 340 m/s and L = 0.85 m, what is f1 when L doubles to 1.70 m?

Fundamental frequency for a tube closed at one end scales as f1 = v/(4L). Doubling the length halves the frequency because f1 ∝ 1/L. With v = 340 m/s and L = 1.70 m, f1 = 340/(4×1.70) = 340/6.8 ≈ 50 Hz. So the fundamental frequency is 50 Hz.

In a tube closed at one end, the fundamental frequency f1 is related to v and L by f1 = v/(4L). If v = 340 m/s and L = 0.85 m, what is f1 when L doubles to 1.70 m?

Prepare for the OnRamps Physics Test with our comprehensive quiz. Engage with flashcards, multiple choice questions, detailed hints, and explanations. Elevate your understanding and boost your confidence for the exam!

In a tube closed at one end, the fundamental frequency f1 is related to v and L by f1 = v/(4L). If v = 340 m/s and L = 0.85 m, what is f1 when L doubles to 1.70 m?

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