In a tube closed at one end, the wavelength of the fundamental harmonic (n=1) is which of the following in terms of length L?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $25.99Unlock all

Prepare for the OnRamps Physics Test with our comprehensive quiz. Engage with flashcards, multiple choice questions, detailed hints, and explanations. Elevate your understanding and boost your confidence for the exam!

Multiple Choice

In a tube closed at one end, the wavelength of the fundamental harmonic (n=1) is which of the following in terms of length L?

Explanation:
A tube closed at one end supports standing waves with a node at the closed end and an antinode at the open end. For the fundamental mode, the tube length is one-quarter of a wavelength. So L = λ/4, which gives λ = 4L. This is the wavelength that fits exactly in the tube for the lowest standing wave. For higher odd harmonics, the length relates to wavelength by L = (2n−1)λ/4, so the next allowed wavelength would be 4L/3, and so on.

A tube closed at one end supports standing waves with a node at the closed end and an antinode at the open end. For the fundamental mode, the tube length is one-quarter of a wavelength. So L = λ/4, which gives λ = 4L. This is the wavelength that fits exactly in the tube for the lowest standing wave. For higher odd harmonics, the length relates to wavelength by L = (2n−1)λ/4, so the next allowed wavelength would be 4L/3, and so on.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy