If a particle's kinetic energy increases from 8 J to 32 J, what is the total work done on the particle?

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Multiple Choice

If a particle's kinetic energy increases from 8 J to 32 J, what is the total work done on the particle?

Explanation:
Work done on a particle equals the change in its kinetic energy. W = ΔK = K_f − K_i. With K_i = 8 J and K_f = 32 J, the change is 32 − 8 = 24 J. So the total work is +24 J, meaning energy was added to the particle by the forces. The other numbers don’t fit the situation: negative 24 J would mean the energy decreased, zero would mean no energy transfer, and 40 J would require an initial kinetic energy of -8 J, which isn’t the case here.

Work done on a particle equals the change in its kinetic energy. W = ΔK = K_f − K_i. With K_i = 8 J and K_f = 32 J, the change is 32 − 8 = 24 J. So the total work is +24 J, meaning energy was added to the particle by the forces. The other numbers don’t fit the situation: negative 24 J would mean the energy decreased, zero would mean no energy transfer, and 40 J would require an initial kinetic energy of -8 J, which isn’t the case here.

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